Chipmunk Physics

Hi,
I found this line surfing through cpSpaceState
line 503 cpSpace.c

Is this doing (1/space->damping)^(-dt)? This is just (space->damping)^dt
The first equation produces error for really small damping (like free space), while the seconds does not. I guess there is a reason for doing this, right?

Thanks

correct me if I'm wrong, but the default value for cpSpace::damping is 1.0.
Therefore free space with no damping would have a damping value of 1.0 and 0.0 would be invalid.
This confused me at the beginning, too, since "no damping" would be 0.0 in my opinion and "full damping" 1.0.

Well, the thought was that you would be able to double the damping value to double the amount of damping. It is a bit confusing though.

but e.g. 0.3 would be really strong damping, and doubling it would be 0.6 which would be a lot less damping in the current setup, or at least that is how it feels to me

Sorry guy,
Yes, you are write that damping 1.0 is no damping. What was the range for damping in the original design? Is 1.0 < damping < \infty, where damping= 1.0 means no damping or was it 0 < damping < 1, where 1 is fully damped?

Anyway, what I was trying to point out is that

pow(1.0f/damping, -dt)

is the same as

pow(damping,dt)

but you save 2 operations.

Thanks!

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/me smacks forehead

Right. I see where you were going with that now.